Question

Helping my son with geometry and I can't figure this out. Any help greatly appreciated... How can I post a picture of the drawing and question?

Answer 1

attach file

Answer 2

Any help with this would be great. I don't understand enough to help my son with this today.

Answer 3

Here is another one - can't figure out together. I think we got #11 & #14 right but no idea how to proceed on 12 & 13.

Answer 4

@khusker You are a great dad. Which questions do you need help with?

Answer 5

Looking at the last one (12). The figure indicates that DE = BE and AE = CE so all you need to do is sove for a value of x that will make AB = CD
If AB = CD then 3x-7 = 2x + 1
Solving for x, we get x=8 To verify 3(8) - 7 = 2(8) + 1
24 - 7 = 16 + 1
17 = 17 It works.

Answer 6

No. 11 You are asked what proves that , <AED = <CEB
Look at what you have, an intersection of two lines and those angles are called what?

Answer 7

Look up definition of vertical angles.

Answer 8

Hey @tinybookworm do you think it is really a Dad helping his son, or a cunning son?

Answer 9

7. Using the triangle exterior angle theorem: \(\textit {An exterior angle of a triangle is equal to the sum of the opposite interior angles.}\)
\(\angle J + \angle JKL = \angle KLM\) <=> \( (6x+4) + (8x + 18)=20x+4\)
Solve for x. Then \(\angle KLM = 20x+4\)

8. \(\triangle KLM\) is a right triangle.

Answer 10

@radar I don't know. Maybe you're right

Answer 11

Or maybe he really wants to help his son. :)

Answer 12

Good job on 12 @radar

Answer 13

Thanks and good work for 7

Answer 14

I just don't believe Kimberly Tarnow is a Dad lol

Answer 15

:)

Answer 16

I worked no. 7. but did not use exterior angle rule, but when I used your method, I got x=3 both ways so it must be right.

Answer 17

Hey Kimberly is back.

Answer 18

@khusker Did you follow 7, and 12 and 11.

Answer 19

This is actually his mom - look at my facebook page - I see my facebook pic is in my profile here - I am not tech savy... Thanks... I am going to look over and see if I understand enough to explain to him Thanks!!!

Answer 20

O.K. Do you have any questions for our solutions of 7., 11., and 12.?

Answer 21

Or does your son have any questions?

Answer 22

Just going over it.... Sorry little slow.. I will let you know :)

Answer 23

ok think if I got this right on #7 - it is asking for the measurement of the angle KLM.... So, after solving for x you get 3 and then you would
20x+4
20(3) + 4 =60 + 4 = 63would be the measurement of this angle - thanks

Answer 24

To expand further on 7. Review the information provided by tinybookworm. Note where he states >j + <JKL = <KLM
that means (6x + 4) + (8x + 18) = <KLM
14x + 22 = <KLM Now note that the problem states that <KLM = 20x + 4
Now we can solve for the measure of angle KLM
14x + 22 = 20x + 4
6x = 18
x = 3 so the measure of 20x +4 is 20 (3) + 4 = 64 degrees.

Answer 25

Yes, you beat me to it lol. Good work.

Answer 26

Is there any others, do you understand vertical angles are equal? (No. 11)

Answer 27

How about 8.? Using the fact that the sum of the angles in a triangle equals 180 degrees

180 = 90 + 20x + 4 + m<M
mM=180 -90 - (20x + 4)
mM = 86 - 20x We know x=3 from 7.
mM= 86-60 = 26 degrees

Answer 28

I visited your facebook page. I liked the pretty photos of a beach

Answer 29

Good luck helping your son, it is so good when parents work with their children.

Answer 30

Thanks - think we got 11 to be sss congruence... Wow I got #12 set up right on there but wasn't sure - makes sense now. Thanks!! Those pics are from the carribean 2 years ago. Austin is in lots of pics but being a teenager doesn't want to take many so lots of them are my daughter :) Thanks so much. I am a degreed accountant and this is the 1st yr I have been struggling showing him math... I guess algebra is my thing

Answer 31

Any pointers for 13 & 14? It is using the drawing from the 11 & 12