Question

cos x + 2 cos x sin x = 0

Answer 1

factor out a cos, so cos(2sin+1)

Answer 2

then split it up, ya get cos x=0 and 2sin x+1=0, two different equations

Answer 3

then what?

Answer 4

so
1. cos x = 0 therefore \(x = \cos^{-1} (0) =?\)
2. 2sin(x) +1 = 0 therefore \(\sin(x) = -\frac{1}{2} \implies x = \sin^{-1} \left(\frac{1}{2}\right) = ?\)

Answer 5

yup

Answer 6

thanks guys

Answer 7

np