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Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do not show that Rn(x) → 0.] f(x) = sin(pix/5)
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Can you do this for g(x) = sin(x)?
I have the thing for sin, but how do i get from sin to what the problem is asking?
put pix/5 where you see an x
Kind of amazing that it is often that simple. One does need to think about convergence, but it just works out pretty often.
Why do you insert pix/5 in x, though?
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The answer comes out to be ((-1)^n)((-pi/2)+(pix/5))^2n all over 2n!
And I'm not even sure where the pi/2 came from.
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