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If f(x)= cscxtanx, then f'(x)=?
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it might help to recognize that csc(x) = 1/sin(x) and tan(x) = sin(x)/cos(x)
cscx tanx = 1/sin(x) * sin(x) /cos(x) = sec(x)
the product rule works though
you beat me to it:)
sec(x) can be re-written as (cos x)^-1 and derive it using the chain rule.
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