If f and g are differentiable functions for all real values of x such that f(2) = 5, g(2) = 3, f '(2) = 1, g '(2) = −2, then find h '(2) if h(x) = f(x) g(x).

13
−13
7
−7

@ganeshie8 :) hi again!

Question

If f and g are differentiable functions for all real values of x such that f(2) = 5, g(2) = 3, f '(2) = 1, g '(2) = −2, then find h '(2) if h(x) = f(x) g(x).

 13
 −13
 7
 −7 

@ganeshie8 :) hi again!

alyssa_xo · Answer

Use the product rule u'v+uv'

anonymous · Answer

how do i do that ? :)

anonymous · Answer

Find the coefficient of the squared term in the simplified form for the second derivative, f "(x) for f(x) = (x3 + 3x2 + 3)(3x3 − 6x2 − 8x + 1) . Use the hyphen symbol, -, for negative values.

I also have that question ^

ganeshie8 · Answer

$$\large \rm   h(x) = f(x) g(x)   $$

ganeshie8 · Answer

Do you see $\rm h(x)$ is defined as a product of two functions, $\rm f(x)$ and $\rm g(x)$ ?

anonymous · Answer

yea :)

ganeshie8 · Answer

So just apply the product rule, whats stopping you ha

anonymous · Answer

i dont know the values of f(x) & g(x)

ganeshie8 · Answer

$$\large \begin{align}\rm  h(x) &= \rm f(x) g(x) \~\
\rm h'(x) &= \rm f'(x)g(x) + f(x)g'(x)\~\
\rm h'(2) &= \rm f'(2)g(2) + f(2)g'(2)\~\

 \end{align}  $$

ganeshie8 · Answer

you are given all the required values to evaluate, just plugin and simplify :)

anonymous · Answer

so that is -7? :)

anonymous · Answer

i have this question now: 
Find the coefficient of the squared term in the simplified form for the second derivative, f "(x) for f(x) = (x3 + 3x2 + 3)(3x3 − 6x2 − 8x + 1) . Use the hyphen symbol, -, for negative values.

ganeshie8 · Answer

Looks good !

anonymous · Answer

thanks ur the best one on here! :D