Question

logx/10=-4

Answer 1

is it \[\log_{x}10\] or \[\log \frac{ x }{ 10}\] ?

Answer 2

x
-
10

Answer 3

x divided by 10

Answer 4

Okay, so then it is a common log and the base is 10. so \[10^{-4}=\frac{ x }{ 10 }\]

Answer 5

now you just have to solve for x

Answer 6

how do i solve for x?

Answer 7

you need to isolate x, so multiply both sides by 10

Answer 8

10^-4 x 10 = 10^-3

Answer 9

so x = 10^-3 or 0.001

Answer 10

\(\bf \large {
log_{\color{red}{ a}}{\color{blue}{ b}}=y \iff {\color{red}{ a}}^y={\color{blue}{ b}}\qquad thus
\\ \quad \\
log\left(\cfrac{x}{10}\right)=-4\implies log_{\color{red}{ 10}}\left({\color{blue}{ \cfrac{x}{10}}}\right)=-4\implies ?
}\)

Answer 11

wouldnt it be 10^-4?

Answer 12

yeap thus

Answer 13

one sec

Answer 14

so basically 10^-4=x?

Answer 15

no, x/10=10^-4 so x=10^-3

Answer 16

okay i kinda get it

Answer 17

\(\bf log_{\color{red}{ a}}{\color{blue}{ b}}=y \iff {\color{red}{ a}}^y={\color{blue}{ b}}\qquad thus
\\ \quad \\
log\left(\cfrac{x}{10}\right)=-4\implies log_{\color{red}{ 10}}\left({\color{blue}{ \cfrac{x}{10}}}\right)=-4\implies {\color{red}{ 10}}^{-4}={\color{blue}{ \cfrac{x}{10}}}
\\ \quad \\
recall \implies a^{{\color{red} n}} \implies \cfrac{1}{a^{-\color{red} n}}\qquad thus
\\ \quad \\
\cfrac{1}{10^4}=\cfrac{x}{10}\)

solve for "x"

Answer 18

x is dividing by 10
you have to move 10 on left side
do to this you have to multiply 10 both side