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Why can't we factorize x^2+49
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Technically, we can factorize it, but then we have to use imaginary number. See, we know that \(a^2-b^2 = (a+b)(a-b)\), right? Let \(b=ci\), we have \[a^2-(ci)^2 = a^2-i^2c^2 = a^2-(-1)c^2 = a^2+c^2\] So factoring it would get you \((a+ci)(a-ci)\)
@sanjii06 Does that make sense? You have learned imaginary number, right?
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