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Trigonometry
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solve over the interval [0,360) 5cot^2 theta -cot theta = 2
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Try to put : \[x=\cot\theta\] And find the solution to the new equation of x :)
i got (1±√41)/10 but i dont know where to go from there
its 1 plus or minus the square root of 41 over 10
OK ! After that you have : \[\cot\theta=\frac{1+\sqrt{41}}{10}\text{ or }\cot\theta=\frac{1-\sqrt{41}}{10}.\] Solve each equation and you will get the solution .
so there is no need for me to convert it to tan before i solve to find the solution?
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The answer would be 0.74, because -0.5 will not fit in the interval.
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