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Mathematics 8 Online
OpenStudy (marissalovescats):

@jim_thompson5910

OpenStudy (marissalovescats):

The answer to this one is online, I just dont understand it.

jimthompson5910 (jim_thompson5910):

ok let me read it over for a sec

OpenStudy (marissalovescats):

Okay

OpenStudy (marissalovescats):

Here's another one, the same problem, different person answering

jimthompson5910 (jim_thompson5910):

sorry I'm reading this real quick to brush up on the rules to apply http://www.mathguy.us/BySubject/Statistics/Scatterplot_Data_Re-Expression_Summary.pdf

OpenStudy (marissalovescats):

Got it

OpenStudy (marissalovescats):

Not got it as in I figured it out but got it as in I'll take a look :P

OpenStudy (marissalovescats):

Here's the next question, I think you know how to do it

jimthompson5910 (jim_thompson5910):

ok took me a bit (longer than I wanted to lol), but I figured out how they got 1.37 + 2.64x

jimthompson5910 (jim_thompson5910):

ok, the first thing that tripped me up was the fact that there were 2 breaking strengths. So I decided to plot both data sets but that was a mess. So I figured "why not average them?" I did so and got this list

jimthompson5910 (jim_thompson5910):

x is the diameter (stays the same) the y's were computed from averaging the breaking strengths. So for instance, in the first row we have 60 and 76 for the breaking strengths. Add them up and divide by 2 (60+76)/2 = 136/2 = 68 the other rows were computed the same way

OpenStudy (marissalovescats):

Yeah I got that when you said average :P

OpenStudy (marissalovescats):

Is that what they want me to do? And then try to streighten it by squaring or logging or square rooting etc?

jimthompson5910 (jim_thompson5910):

ok great, if you plot these points, you get this graph

jimthompson5910 (jim_thompson5910):

the points seem to fall on a parabola (parabola opens upward) so we'll use the quadratic model shown on the pdf

OpenStudy (marissalovescats):

And this is with them averaged yes?

jimthompson5910 (jim_thompson5910):

yes correct

jimthompson5910 (jim_thompson5910):

so what you do is apply the square root function for every y value of the averaged breaking strengths to get this new list

jimthompson5910 (jim_thompson5910):

the set of points generated gives this graph

jimthompson5910 (jim_thompson5910):

that data set is much more linear, the regression line I get with that last data set is y = 1.3730408959x + 2.6478064917 which is the same as y = 2.6478064917 + 1.3730408959x and the person just rounded to 2 decimal places (with roundoff error? not sure) y = 2.64 + 1.37x

jimthompson5910 (jim_thompson5910):

also, this page gives a good table on which method to use and which variable to transform http://stattrek.com/regression/linear-transformation.aspx

jimthompson5910 (jim_thompson5910):

anyways, once you get this |dw:1416194957531:dw| you plug in x = 25 and then evaluate. Afterwards, you square both sides to get y-hat.

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