P(t) = 6e^0.2t/(4+2e^0.2t) determine average rate of change of the population for 0<=t<=20
Find a time at which instantaneous rate of change of population is equal to the average rate of change
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OpenStudy (anonymous):
@Mertsj
OpenStudy (anonymous):
@dumbcow
OpenStudy (swissgirl):
Firstly find f(0) and f(20)
Then we need to find the average rate of change from 0<t<20
So we would use the following formula
\[\text {Average Rate of Change } =\frac{f(20)-f(0)}{20-0}\]
OpenStudy (anonymous):
Ok yes and I got like .0947
OpenStudy (dumbcow):
set that equal to P'(t) ..... solve for t
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OpenStudy (dumbcow):
use quotient rule for finding derivative
OpenStudy (fibonaccichick666):
You can always relate rate of change to derivative(side note). It essentially implies take the derivative :)
OpenStudy (anonymous):
So check is this right 1.2e^.2t/(4+2e^.2)^2
OpenStudy (anonymous):
Opps Should be 1.2e^.2t/(4+2e^.2t)^2
OpenStudy (anonymous):
Is that right ?
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OpenStudy (dumbcow):
pretty close ... a 2 can be factored out of denominator
OpenStudy (dumbcow):
1.2e^.2t/(2+e^.2t)^2
OpenStudy (anonymous):
So now how do I solve when set equal to .0947 ? Cross multiply ?
OpenStudy (dumbcow):
yeah, looks like you will need to distribute it out and get a quadratic
OpenStudy (anonymous):
So i get 0.3788e^.2t+.0947e^.4t+0.3788=1.2e^.2t
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OpenStudy (anonymous):
@FibonacciChick666
OpenStudy (fibonaccichick666):
hm?
OpenStudy (anonymous):
How do now solve this
OpenStudy (fibonaccichick666):
for instantaneous? get the derivative and evaluate the difference between 0 and 20
OpenStudy (fibonaccichick666):
sorry misread, no just do what dumbcow did
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OpenStudy (anonymous):
But thats where I went but how do I solve from there ?
OpenStudy (fibonaccichick666):
combine the .2 terms to get a quadratic then use e^.4t=x^2
OpenStudy (fibonaccichick666):
That I think is what I'd do
OpenStudy (anonymous):
Ah :)
OpenStudy (anonymous):
?? I am getting imaginary numbers
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OpenStudy (anonymous):
I did ln and got a number thanks
OpenStudy (anonymous):
@iambatman
OpenStudy (anonymous):
@Spectrum
OpenStudy (anonymous):
@sourwing
OpenStudy (anonymous):
Please help I just want to finish this one
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OpenStudy (anonymous):
other people already told you how to do it. Just find the slope
OpenStudy (anonymous):
So I found derivitave an set it equal to the 0.0947 how now do I solve for t
OpenStudy (anonymous):
??
OpenStudy (anonymous):
@Directrix
OpenStudy (anonymous):
How do I solve this help!
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