Question

Help! ASAP please! I only have until tomorrow morning to figure this out!

Answer 1

1. Is the relationship between velocity and centripetal force a direct, linear relationship or is it a nonlinear square relationship? Explain the answer using your graphs of Fc vs. v and Fc vs.v2. What is the precise mathematical relationship between velocity and centripetal force?

Answer 2

My data...

Answer 3

I know that the centripetal force is directly proportional to the square of the velocity and I think it might be nonlinear square but I'm not sure why.

Answer 4

Sorry I thought I was in OpenStudy Feedback, haha my bad!

Answer 5

Also: For Part 1, which of your two graphs verifies that Fc=mv^2/r? Is this relationship a linear relationship? Compare the equation for a line through the origin, y = mx, to the equation, and explain what the slope of the graph of Fc vs. v2 represents. Remember that the m in the equation for a line represents the slope, and the m in the centripetal force equation represents the mass of the stopper.

Answer 6

just by the looks of the graphs it looks like centripetal force vs velocity is non-linear square relationship and the centripetal force vs velocity^2 graph is linear

Answer 7

Thank you so much! You're a life saver!

Answer 8

Could you possibly help with another? For Part 1, which of your two graphs verifies that Fc=mv^2/r (which I know is the precise mathematical relationship between centripetal force and velocity)? Compare the equation for a line through the origin, y = mx, to the equation, and explain what the slope of the graph of Fc vs. v2 represents.

Answer 9

I think the centripetal force (Fc) vs velocity^2 verifies Fc=mv^2/r. Am I right?

Answer 10

And also, I don't have any idea what it's asking me to do with the whole comparing thing. I think I'll be able to do it by myself if I just understood that part a little better.

Answer 11

@whead1 I would really appreciate it but if you don't have the time, I understand. :)