keep in mind that the range of arctan(x) is -pi/2 < y < pi/2
jimthompson5910 (jim_thompson5910):
so you're either in quadrant I or quadrant IV
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OpenStudy (anonymous):
11,-11 is quandrant 3 at the beginning of the problem. also im not sure if your taking all the steps necessary. look at a similar example at the last couple of steps
OpenStudy (anonymous):
hold on imma upload similar example from book
jimthompson5910 (jim_thompson5910):
(11,-11) is in quadrant 4
OpenStudy (anonymous):
oh ur right. i see now, i apologize
jimthompson5910 (jim_thompson5910):
thats ok
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OpenStudy (anonymous):
but i still think you are skipping a step. im aiting on a email from my phone to upload
OpenStudy (anonymous):
waiting*
OpenStudy (anonymous):
OpenStudy (anonymous):
see the last coiple steps i am referring to by the stars i drew on the problem
OpenStudy (anonymous):
(-1,sqrt3) were the original w,y coordinates for this problem
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jimthompson5910 (jim_thompson5910):
they did that correctly
jimthompson5910 (jim_thompson5910):
notice how the point (-1, sqrt(3) ) and the angle 2pi/3 are both in quadrant 2
jimthompson5910 (jim_thompson5910):
however, with your problem, none of the angles are in quadrant IV
OpenStudy (anonymous):
that step is the same on a problem that lies in quadrant 4 as well, do you think that step needs to be applied to this problem?
jimthompson5910 (jim_thompson5910):
3pi/4 is in quadrant 2
3pi/4 radians = 135 degrees
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jimthompson5910 (jim_thompson5910):
-3pi/4 radians is coterminal to 5pi/4 radians (add 2pi)
OpenStudy (anonymous):
will you "draw" your work for the tangent formula side of my problem please?
jimthompson5910 (jim_thompson5910):
5pi/4 radians = 225 degrees
so the angle is in quadrant 3
jimthompson5910 (jim_thompson5910):
what do you mean?
OpenStudy (anonymous):
one moment for another attachment please
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OpenStudy (anonymous):
OpenStudy (perl):
jim doesnt mind if i take over?
OpenStudy (perl):
what number?
OpenStudy (anonymous):
@jim_thompson5910 does that look correct?
jimthompson5910 (jim_thompson5910):
you are correct until you reach the point where you say 180 - 45 = 135
that rule of 180 - theta only works if you are in quadrant 2
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OpenStudy (perl):
by the way, this is why i use the 4 quadrant arctangent function, called atan2
OpenStudy (anonymous):
ooh in q4 it should be 360?
jimthompson5910 (jim_thompson5910):
yeah if you want to find the reference angle in quadrant 4
jimthompson5910 (jim_thompson5910):
but the angle should be -pi/4 like you got or 7pi/4
jimthompson5910 (jim_thompson5910):
none of the answer choices have that
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OpenStudy (perl):
this question has a typo
OpenStudy (perl):
the multiple choice typo :o
jimthompson5910 (jim_thompson5910):
yeah
OpenStudy (perl):
choose
e. my teacher does not edit for typos
OpenStudy (perl):
that would be funny if that was a test
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OpenStudy (perl):
one of the multiple choices
OpenStudy (anonymous):
dont say that, this makes the 7th freakin typo i found already
OpenStudy (perl):
e. none of the above : my teacher does not edit for typos
OpenStudy (anonymous):
this is on a scantron though, e wont be counted as an answer period
jimthompson5910 (jim_thompson5910):
well it's a typo, idk what else to tell you
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OpenStudy (perl):
do you understand that -45 degrees = 360 + (-45) degrees ?