Question

how can I find the derivative of the following function.

S(t)=t+(9/(t+1))+1

Answer 1

ds/dt as dy/dx

Answer 2

the only rule I really understand for derivatives is the power rule and I don't know how to apply it to fractions

Answer 3

\[ds/dt=t+\frac{ 9 }{ t+1}+1\]

Answer 4

okay

Answer 5

here you have 3 parts

Answer 6

ds/dt=t
ds/dt=(9/(t+1))
ds/dt=1

Answer 7

i think you know the dreiv. of the 1st one and the last one

Answer 8

the derivative of the first is 1 and there isn't one for the last one right?

Answer 9

the second one it has his one rule

Answer 10

yes about the first one.

would you mean by there isn't one for the last one? do mean the answer is (0) or there isn't one in the equation

Answer 11

the answer is 0

Answer 12

I honestly thought it meant that there wasn't one present, but I guess you are implying that if there is not a variable then the derivative=0

Answer 13

df/dx= for a constant =0

Answer 14

2nd (f'*g-fg')/g^2

Answer 15

this the rule
f=9
g=t+1

Answer 16

so my answer would be 1-(9/(t+1)^2)

Answer 17

yes

Answer 18

awesome! thanks. Also, how would I solve that equation for t?

Answer 19

never mind I see it. thank you