CAN SOMEONE PLEASE HELP ME ???? THIS IS SO CONFUSING. PLEASE PLEASE PLEASE HELP ME? A quadratic equation is shown below: x^2 + 5x + 4 = 0 Part A: Describe the solution(s) to the equation by just determining radicand. Show your work. Part B: Solve 4x^2 -12x + 5 = 0 using an appropriate method. Show the steps of your work, and explain why you chose the method used. Part C: Solve 2x^2 -10x + 3 = 0 by using a method different from the one you used in Part B. Show the steps of your work.
@ganeshie8
anybody?
the radicand is the value inside the square root if you are using the general quadratic formula... its commonly known as the discriminant \[\Delta = b^2 - 4ac\] you have a = 1, b = 5 and c = 4 so substitute them and get a value
oh ok srry wait a sec
the conditions for the discriminant \[\Delta > 0 \] two unequal roots... if it is a perfect square the then the roots are rational. \[\Delta = 0\] two equal or repeated roots... the quadratic factors to a perfect square. \[\Delta < 0\] the roots and complex... and the term no real roots is used to describe them. hope it helps
5^2 - 4 (1) (4)
thats correct... so what value does it have...?
-6
oops should read \[\Delta > 0\] two real unequal....
ummm try again 25 - 16 =
oh srry did it in my head real quick
9
great so 9 > 0 so real unequal roots and 9 is a perfect square so the roots are rational. that's it
ok so that 's part a right ?
that's correct...
ok could you help me with part b and c if not thats fine
ok... so for B.... you could use the general quadratic formula \[x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}\] a = 4, b = -12 and c = 5 but it can be factored...
it depends on when method you are confident with.
ok so for part c i could factor it right?
I'd factor B and use the General Quadratic formula for C
ok great thank you uhm do u mind helping me with one more i got most parts down but some i dont get
ok... what do you need a hand with..
A Labrador leaps over a hurdle. The function f(t) represents the height of the Labrador above the ground, in inches, at t seconds: f(t) = -16^t2 + 20t A foxhound jumps over the same hurdle. The table shows the height of the foxhound above the ground g(t), in inches, at t seconds: Time (t) g(t) 0 0 0.4 7.44 0.6 9.24 0.75 9.76 1.0 9 1.50 0 Part A: Compare and interpret the maximum of f(t) and g(t)? (4 points) Part B: Which function has a greater x-intercept? What do the x-intercepts of the graphs of f(t) and g(t) represent? (4 points) Part C: Determine the y-intercepts of both functions, and explain what this means in the context of the problem. (2 points)
srry im not typing something is wrong with my internet
it keeps saying that im typing but im not
this looks like a test... the max height for g(t) can be read off the table max height is 9.76 when t = 0.75 for f(t) you need to find the line of symmetry, the max height is on this line \[t = \frac{-b}{2a}\] you have b = 20 and a = -16 so substitute and find the value of t, then substitute it into f(t) to find the max height. of now for part B 0 = -4t(4t - 5) find the values of t than make the equation true... these are the times when the dog and fox are on the ground. In both cases there is a solution t = 0.... you need to find the other value in g(t) find the t values where g(t) = 0 hope it helps
yeah it is a test hope you dont mind
I do.. so I'll leave you to finish it...
ok thanks tho u have been a great help
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@dfjaijdkjlakjf
ok im srry @TheSmartOne
but he explained it to me
Yes but posting test questions is cheating...
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