Question

sin2x/1+cos2x=tanx

how do i do this

Answer 1

sin2x=2sinxcosx

Answer 2

what you need?

Answer 3

i dont know how sin2x/1+cos2x equals tanx

Answer 4

trig identities

Answer 5

okay

Answer 6

sin^2(x)+cos^2(x)=1

Answer 7

sin^2(x)= (1-cos(2x))/2

Answer 8

maybe it's \[\frac{\sin(2x)}{1+cos(2x)}\]

Answer 9

sin(2x)=2*sin(x)cos(x)
cos^2(x)=1/2(1+cos(2x)
cos(2x)=2*cos^2(x)-1

Answer 10

sin^2(x)+cos^2(x)=1
multply the eq by 2 and cos(x)
2cos(x)sin^2(x)+2cos(x)cos^2(x)=2cos(x)
sin(2x)*sin(x)+2cos(x)cos^2(x)=2cos(x)
sin(2x)*sin(x)+2cos(x)(1/2+cos(2x)/2)=2cos(x)
divide by cos (x)
sin(2x)*tan(x)+1+cos(2x)=2
take the 1 to the other side
sin(2x)*tan(x)+cos(2x)=1

Answer 11

look at it might help....it needs some thinking

Answer 12

...\[\frac{ \sin(2x) }{ 1 }+ \cos(2x)= \tan(x)\]
if this the equation like that ..... then something wrong here. i put value for x and the amswer are not the same....