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Mathematics 22 Online
OpenStudy (anonymous):

How did they get this answer??

OpenStudy (anonymous):

what answer

OpenStudy (anonymous):

I got that the inverse tangent of -10 was equal to -84.3--but the answer is 95.7.

OpenStudy (anonymous):

I dont understand what I'm doing wrong,

OpenStudy (anonymous):

hmm i think the answer is wrong. i don't think tan^-1 goes beyond 90.

OpenStudy (perl):

they added 180 degrees to arctan (-10)

OpenStudy (perl):

because the answer should be in quadrant 2, not quadrant 4

OpenStudy (perl):

thats the only logical conclusion. do you have all the steps leading up to this point. i am reverse engineering at this point

OpenStudy (campbell_st):

its to do with the quadrants... tan is negative in the 2nd and 4th quadrants... the solution given is a 2nd quadrant angle

OpenStudy (anonymous):

make sure you degrees. OR radians.

OpenStudy (campbell_st):

so the 2nd quadrant angle is 180 - @ = 180 - 84.3 = 95.7

OpenStudy (campbell_st):

so perhaps there is a restricted domain or they forgot the 4th quadrant angle 360 - 84.3 = 275.7

OpenStudy (perl):

the problem here is that if say your terminal point is (-1, 1 ) or (1, -1) , you will get the same arctan arctan ( 1/ -1) = arctan (-1/1) = arctan (-1)

OpenStudy (anonymous):

|dw:1416203470881:dw|

OpenStudy (perl):

this 'problem' can be solved with a two argument arctangent function called atan2 http://en.wikipedia.org/wiki/Atan2 or you can just visually inspect your point and make the necessary adjustment

OpenStudy (anonymous):

|dw:1416203596736:dw|

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