Question

secx + tan=1 are you allowed to square these ?

Answer 1

yeah you are allowed. Will you post the problem in which you are going to apply ?

Answer 2

allowed

Answer 3

It says solve on the interval 0<=x<2pi secx+tanx=1
I got to -1+1/cos+sin/cos=0

Answer 4

u know the answer

Answer 5

will i post a solution in a non-trivial way?.@Lorayne

Answer 6

No I am looking at the examples and lost... no idea why you are allowed to square both sides to make it sinx^2+Cosx^2=1

Answer 7

@Lorayne check the attachment. I am sure you can proceed after that

Answer 8

Thank you I am looking at it now :)

Answer 9

@Lorayne did you get the solution? Next all you have to do is just find the x values in the given range.

Answer 10

Sorry this is my first one of these and still learning how you got the sin on the bottom... did you use sin^2+1 to exchange it ?

Answer 11

cos2x =cos ^2 x- sin ^2 x. I used this formula

Answer 12

ok, looking.

Answer 13

ok how do you get the pi over 4 ?

Answer 14

tan (a+b)=(tan a+tan b)/(1-tan a tanb) : formula.

Answer 15

ok I just learned that in the last section. I don't have it in my example so I wasn't sure

Answer 16

hmm...

Answer 17

and when tan A=tan B, then A=npi+B, where n is an integer

Answer 18

I am going back in the previous section and rereading lol I am missing steps