Question

What is the inverse function of
f^(-1(x) ) if f(x)=√((3x-1) )+2

Answer 1

To find inverse functions,

1. set f(x) = y = \(\sqrt{3x-1} +2\)

2. switch the x and y around : x = \(\sqrt{3y-1}+2\)

3. solve for y now

Answer 2

can you walk me through it please

Answer 3

\[x -2 = \sqrt{3y-1}\]\[(x-2)^2 = (\sqrt{3y-1})^2\]\[(x-2)^2 = 3y -1\]\[(x-2)^2 +1 =3y\]\[y= \frac{(x-2)^2+1}{3}\]

Answer 4

Which part are you confused about currently? :o

Answer 5

wow. thanks.....I forgot about squaring both sides...I was only squaring one side

Answer 6

Yeah, at first I thought hey, we got it in terms of x = something... why not just square both sides?

Answer 7

then i realized that if i squared the right side with the 2 still there, it would be really messy and complicated, so i subtracted 2 from both sides before squaring both sides and getting rid of the square root.

Answer 8

yeah! thank!(:

Answer 9

First step : change f(x) to y

2nd step: switch the x and y to indicate you're taking the inverse of the function

3rd step: solve for y after inverting the two variables

4th step: once you get your equation in terms of y (again) change it to \(f^{-1} (x)\) to indicate that it is the inverse.

Answer 10

Can you walk me through the steps on finding the domain and rang for f(x)=logbase4(x+2)?

Answer 11

*range