decompose 1/x^2(x^2+1)^2
into partial fractions?
yes please :(
The first term in the denominator is the x^2 term
ohhhh that's why i can't get the right answer.. TY very much!!!
what partial fraction terms will the x^2 term decompose into?>
wait so i will write the first term as A/x^2?
Using your partial fraction table. it might help to write x^2 as (1*x+0)^2
for should two fractions from the first term
so i will write it as A/x + B/x^2 for the first term?
yes, that's good. now lets look at the second term
so for the second term it will be (Cx+D)/(x^2+1) + (Ex+F)/(x^2+1)^2?
Yes, great work, now we just have to find A, B, C, D, E, & F
Ok i'll be back later
So far, we have \[\frac1{x^2(x^2+1)^2}=\frac Ax + \frac B{x^2}+\frac{Cx+D}{x^2+1} + \frac{Ex+F}{(x^2+1)^2}\]
okay okay...i'm already solving for the values.
is this right? A=0, B=1, C=-1, D=0, E=0, and F=1?
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