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Mathematics 10 Online
OpenStudy (anonymous):

Use a calculator and inverse trigonometric ratios to find the unknown side lengths and angle measures. Round lengths to the nearest hundredth and angle measures to the nearest degree. (Show all work to support each response.)

OpenStudy (anonymous):

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

Can you please tell me how I work this out I do not need the answers

OpenStudy (anonymous):

Please sir @igreen

OpenStudy (igreen):

Sorry, my idiot brother messed up what I was writing. Hold on, let me re-write it.

OpenStudy (igreen):

Use the Pythagorean Theorem, we use it to find lengths of right triangles. \(a^2 + b^2 = c^2\) Where a & b are the sides and c is the hypotenuse. Plug in what we know: \(a^2 + 4^2 = 5^2\) Simplify exponents: \(a^2 + 16 = 25\) Subtract 16 to both sides: \(a^2 = 9\) Square both sides: \(a = \sqrt 9\) Can you square that? @EuniceOB97

OpenStudy (anonymous):

Yes is it 3? @iGreen

OpenStudy (igreen):

Yep, so the missing side length is 3.

OpenStudy (anonymous):

THank you so much

OpenStudy (anonymous):

Can you please help me with the next two I need it for graduation

OpenStudy (igreen):

Hold on, I still have to help you find the angle measurements, right?

OpenStudy (anonymous):

YES you right thank you

OpenStudy (igreen):

\(\tan C = \dfrac{4}{3}\) Use the inverse tangent function: \(\tan^{-1}(\tan C)=\tan^{-1}(\dfrac{4}{3})\) \(C = \tan^{-1}(\dfrac{3}{4})\) \(C \approx 53º\) So that's the angle measurement of Angle C. Now to find the last angle measurement, we can add the two angles we have already and subtract that by 180, because a triangle's sides add up to 180 degrees. \(53º + 90º = 143º\) \(180º - 143º =~?\) @EuniceOB97

OpenStudy (igreen):

If you see those question marks, reload the page.

OpenStudy (anonymous):

Thank you so much would you mind doing two others ?

OpenStudy (igreen):

Can you subtract 180 - 143?

OpenStudy (igreen):

Sure, just close this one and open a new one.

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