Say you took warm water heated to about 75 degrees Celsius and placed it in a styrofoam cup and measured the temperature before the placing of ice in the cup. Then you took ice in a paper towel and measured the mass of it and the paper towel, then you placed the ice in the cup. When the ice was melted the temperature and mass was recorded, how would you find the heat of fusion? The data you recorded was the mass of calorimeter mass of calorimeter and warm water temperature before adding ice mass of ice and paper towel mass of paper towel temperature once ice has melted mass end You have to use a graph...
To begin with this, what is the "heat of fusion"?
the energy in J/g to melt ice
okay good, so the graph will look like this: |dw:1416276649055:dw|
|dw:1416276809160:dw|
what is q?
q is heat
ok
are you able to figure this out now?
so how would I use the temperature/q get joules/g, would i use specific heat?
hm you would need to use the calorimeter equation \(q=m_{water}*C_p*\Delta T\) so the equation for the system would be: \(\sf \large -q_{hot}=q_{ice}\) \(\sf \large- m_{hot}C_p(T_f-T_i)=m_{cold}C_p(T_f-T_i)+H_{fus}*m_{ice}\)
if i were to repeat this experiement five times and then I have to use graphs, would I just have two graphs
both graphs would have the x axis be the mass of ice
for the first graph, I would have the y axis be the change in temperature as calculated by the very first temperature reading-the final temperature reading, and the second graph would have the y-axis as the change in temperature as calculated by the final temperature reading minus zero
|dw:1416277704766:dw|
|dw:1416277861200:dw|
hmm i'm really not sure i understand why you would use the mass of ice as the x-axis. Was this told to you?
yeah
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