Question

Could someone please help me with this problem? I am unfamiliar with point-slope/slope intercept. So I am unsure how to go about the conversion.
Thank you!!

Rewrite the equation of a line in point-slope form to slope intercept form: y-2 = 2/3 (6x+9)

Answer 1

hmm lemme redo that

\(\bf y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad\\
\qquad \uparrow\\
\textit{point-slope form}
\\ \quad \\
y={\color{green}{ m}}x+y-intercept\\
\qquad \uparrow \\
\textit{slope-intercept form}\)

so in short
notice the number to the right-side of the "y", that's the y-coordinate
notice the number to the right-side of the "x", that's the x-coordinate

"m" is the slope, or the number in front of the parentheses

so you expand all those and simplify them to make it look like the slope-intercept form

so you'd end up with y = "some number" x + "some other number"
like for example y = (3/5) x + 11 or so

Answer 2

you could just start it up by simply
solving the equation for "y", so the "y' would be left on the left-hand-side by itself

Answer 3

lemme make a quick example
say the point-slope form is y - 3 = 5(x+1)
y-3 = 5x+5
y = 5x+5 +3
y = 5x+8 <---- slope-intercept form

Answer 4

http://webapps.kpbsd.k12.ak.us/moodle/content/FLVS_ALG1/educator_algebra1_v10_gs/module04/imagemod04/04_06_02a_01.JPG