HHHEEEEEELLLPPPP INVERSE FUNCTIONS
\[f(x)= -2(x+1)^2-4\]
To find the inverse function we first switch x and y and then solve for y.
same as you'd a linear one do the variable "switcharoo" and solve for "y"
^^ ditto
naaaaaaaa id rather not
\[x= -2(y+1)^2-4\]
yes
i dont know what to do after that. Do i solve for y?
yes.
well... do you know how to simplify linear equations? is the same thing
say how would you simplify or solve for "a" b = -2a -4 ?
wouldnt you add 4\[x+4 = -2(x+1)^2\]
well... yes... "y" on the right-side of course... so \(\bf f(x)=y= -2(x+1)^2-4\qquad inverse\implies x=-2(y+1)^2-4\impliedby f^{-1} \\ \quad \\ x+4=-2(y+1)^2\implies \cfrac{x+4}{-2}=(y+1)^2\quad \textit{ taking }\sqrt{\qquad } \\ \quad \\ \sqrt{\cfrac{x+4}{-2}}=\sqrt{(y+1)^2}\implies \sqrt{\cfrac{x+4}{-2}}=(y+1)\implies ?\)
\[\sqrt{(\frac{ x+4 }{ -2 })} -1\] would it be that?
@jdoe0001
yes
is that the answer?
yeap that's the "inverse relation" mind you that is NOT a function.... but an inverse relationship expression
alright, thank you. Could you help me with one more please?
sure just post anew, thus if I dunno, someone else may know, and we revise each other
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