Mathematics
11 Online
OpenStudy (anonymous):
How do I find the equation for a line on a graph?
Either an explanation or a link to an explanation would be appreciated! Thanks.
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jimthompson5910 (jim_thompson5910):
Do you have the graph?
OpenStudy (anonymous):
No, but I have two points. (8,3) and (4,3)
jimthompson5910 (jim_thompson5910):
what is the slope of the line through those points?
OpenStudy (anonymous):
Erm... heh. I don't know? Sorry...
jimthompson5910 (jim_thompson5910):
you would use the slope formula
\[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\]
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jimthompson5910 (jim_thompson5910):
(x1,y1) is your first point
(x2,y2) is your second point
OpenStudy (anonymous):
So m=0/-4?
jimthompson5910 (jim_thompson5910):
which reduces to 0
jimthompson5910 (jim_thompson5910):
the slope of m = 0 means that we have a completely flat horizontal line
jimthompson5910 (jim_thompson5910):
now we turn to y = mx+b
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jimthompson5910 (jim_thompson5910):
m = 0
jimthompson5910 (jim_thompson5910):
x and y are from either point you pick
so let's say you pick (8,3) that means x = 8 and y = 3
jimthompson5910 (jim_thompson5910):
so...
y = mx+b
3 = 0*8 + b
b = ???
OpenStudy (anonymous):
b=3
OpenStudy (anonymous):
Right?
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jimthompson5910 (jim_thompson5910):
m = 0 and b = 3
y = mx+b
y = 0x + 3
y = 3
jimthompson5910 (jim_thompson5910):
so the final answer is y = 3
OpenStudy (anonymous):
Okay, thank you! :)
jimthompson5910 (jim_thompson5910):
you're welcome