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OpenStudy (anonymous):
HHHEEEELLLPPPP INVERSES f(x)e^2x
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OpenStudy (anonymous):
@jdoe0001
OpenStudy (jdoe0001):
hmm have you covered logarithms yet?
OpenStudy (jdoe0001):
I assume is \(\large \bf f(x)=e^{2x}\)
you'd end up with a logarithmic function though, thus... have you covered logarithms yet?
OpenStudy (anonymous):
would you take the natural log?
OpenStudy (anonymous):
and yes
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OpenStudy (anonymous):
\[\frac{ x }{ e^2 }\]
OpenStudy (anonymous):
Maybe?
OpenStudy (anonymous):
\[\ln x =\ln e ^{2y}\]
OpenStudy (anonymous):
then move the 2y in front?
OpenStudy (jdoe0001):
ok.... so...
let us use the log cancellation rule of .
actually... yes... let us use the exponent instead
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OpenStudy (anonymous):
and In e = 1
so it would be...\[\ln x=2y\]
OpenStudy (anonymous):
oh okay
OpenStudy (jdoe0001):
\(\bf f(x)=y=e^{2x}\qquad inverse\implies x=e^{2y}
\\ \quad \\
log_{\color{brown}{ e}}x=log_{\color{brown}{ e}}({\color{brown}{ e}}^{2y})\implies log_e(x)=2y{\color{purple}{ log_e(e)}}\implies ln(x)=2y\cdot {\color{purple}{ 1}}
\\ \quad \\
\cfrac{ln(x)}{2}=y\)
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