Find the derivative of the equation in the comments

Question

anonymous · Answer

$$y=\cot^2(\cos \theta)$$

anonymous · Answer

This requires chain rule, what have you done?

anonymous · Answer

A better way to look at this is, $$y= \left( \cot(\cos \theta) \right)^2$$

anonymous · Answer

It's like saying $$y=\sin^2x \implies y = [sinx]^2$$

anonymous · Answer

Yes I have done that and started this step $$2\cot(\sin \theta)$$

anonymous · Answer

Use the chain rule now find the derivative of cot(sintheta)

anonymous · Answer

Meaning you find the derivative of cot and then the inside which is sin theta, you see can see a pattern :P

anonymous · Answer

the derivative of cot is -csc and then I don't understand the sin theta

anonymous · Answer

I meant costheta haha I was just looking at my example and said sintheta :p

anonymous · Answer

and derivative of cotx is -csc^2x

anonymous · Answer

$$2\cot(\sin \theta)*(-\csc^2 \theta)*(\sin \theta)'$$

anonymous · Answer

So now you have to find the derivative of sin theta and you're done and can simplify and stuff if ya like.

anonymous · Answer

I don't understand how to do that. That's the part I need help with

anonymous · Answer

The derivative of sin theta?

anonymous · Answer

Yes I know it sounds dumb but I don't get it

anonymous · Answer

Uhg I keep putting sin theta, it should be cos theta, I'm so sorry >_>

anonymous · Answer

You did nothing wrong! Just replace my sin theta with costheta and find the derivative of costheta

anonymous · Answer

So the derivative of costheta is -sintheta right?

anonymous · Answer

Yes :)

anonymous · Answer

Sorry about my errors earlier, I just kept going along with my example haha, you did very well.

anonymous · Answer

Its okay thanks :)

anonymous · Answer

Np ^.^