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Find an equation of the tangent line to the curve at the given point. y = sin(sin x), (3π, 0)
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what is y' equal to?
sin(sin(x))
y is equal to that, you have to derive both sides with respect to x to get y '
or dy/dx
use the chain rule
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The thing is I don't understand the chain rule. I'm taking my first online class and my teacher is horrible.
what is the derivative of sine?
cosine
ok right so the chain rule the derivative of the sine of something is the cosine of something, times the derivative of the something for example, \[\frac{d}{dx}[\sin(x^2)]=\cos(x^2)\times 2x\] and \[\frac{d}{dx}\sin(e^x)=\cos(e^x)\times e^x\]
in your case you have \[\sin(\sin(x))\] so the derivative is \[\cos(\sin(x))\times \cos(x)\]
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