Please, please, please explain where I went wrong.
Let a, b, c be real numbers such that \(a + b + c=6\) and \(ab + bc + ca = 9.\) If exactly one root of the equation \(x^2 - ( m+2)x + 5m = 0 \) lies between the minimum and maximum value of \(c\), find the number of possible integral values of \(m\). So \(a^2 + b^2 + c^2 = 18\) according to the question, meaning that the minimum value of \(c\) should be \(-\sqrt{18}\) and the maximum value of \(c\) should be \(\sqrt {18}\). Then I solved the inequality \(f(-\sqrt{18})\cdot f(\sqrt{18}) <0\) and got 10 integral values for \(m\), which apparently is wrong. WHYYYYYYYYYY?!
Pretty sure that condition doesn't need any discriminant or stuff. Am I missing something?
I follow everything so far up to the end where you did f(-c)*f(c)<0 Not sure why that would work out.
m+2 +/- sqrt(m^2+2m+4-20m) -sqrt18<--------------------------- < sqrt 18 2
Intermediate Value Theorem. I have to make a root lie between -sqrt18 and +sqrt18.
Why not just count all the integers between \[\LARGE -3\sqrt{2} \le m \le 3 \sqrt{2}\]
i didn't get this part `which apparently is wrong.` why do you think the count is wrong ?
Because that's the wrong answer, of course.
why
Maybe because this is a parabola and they are specifying "EXACTLY one root"
Are you asking why it is the wrong answer? Probably because I made a mistake along the way. :|
@Kainui IVT works for that.
It does? I am imagining you having two roots even though you are looking for answers that only give one.
no, im asking why do you think it is "apparantely" the wrong answer..
I don't, but the questionmaker does. lol Could you guys solve this and confirm the answer as 10?
based on your work, if u get 10 integer solutions then it is the right answer. i don't see anything wrong in ur work or in applying IVT
hey explain IVT
Oh wait, you want only one root to lie between -c and c, i think you are not accounting for both roots lying betwee -c and c
That's what I'm saying lol
But if both roots lie between -c and +c, then f(-c) * f(c) > 0. :P
Oh yes you're right right !
ohh i get it cool
I still don't get it. Guess I never learned the IVT
this is a positive parabola
no no it make sesne basically u know hwo at the root its a zero
see if that gif confirms your count parth
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