x^2+12x=-36
Use the quadratic formula to solve each equation.

Question

x^2+12x=-36
Use the quadratic formula to solve each equation.

jhannybean · Answer

Set it to quadratic equation : $\large \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$

anonymous · Answer

This is what I have so far
$$x^{2}+12x=-36 $$
$$x^{2}+12x+36=-36+36 $$
$$x ^{2}+12x +36=0$$
$$x=\frac{ -(12)\pm \sqrt{(12)^{2}+4(1)(36)} }{ 2(1) }$$
$$x=\frac{ 12\pm \sqrt{144+144} }{ 2 }$$
$$x=\frac{ 12\pm \sqrt{288} }{ 2 }$$
$$x=\frac{ 12\pm12\sqrt{2} }{ 2 }$$

anonymous · Answer

whoops but place a - at the first 12 i forgot to place them here on this

jhannybean · Answer

it should be $$x=\frac{ -(12)\pm \sqrt{(12)^{2}\color{red}-4(1)(36)} }{ 2(1) }$$

anonymous · Answer

ahhh ok I think thats what i may have done wrong thank you! Im going to check

anonymous · Answer

ugh, can't believe i missed that! Thank you so much!

jhannybean · Answer

No problem :) don't forget the -ve infront of the first 12 though!

anonymous · Answer

it coulde simply x^2+12x=-36
x^2+12x+36=0
(x+6)(x+6)=0
x+6=0
x=-6