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OpenStudy (anonymous):
help w/ geometry
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OpenStudy (anonymous):
If you can take me through the steps, that'd be awesome.
OpenStudy (anonymous):
For first one, the two solids are similar so we can say that :
\[\frac{V_2}{V_1}=a^3\]
Where a is number !
Cam you find
\[a?\]
OpenStudy (anonymous):
is this for the first or second one?
OpenStudy (anonymous):
It is for the first one !
OpenStudy (anonymous):
don't I do like 4* 8 /125 (2/3) or something. I don't remember...
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OpenStudy (anonymous):
or maybe I switch the 8 and 125.
OpenStudy (anonymous):
nvm
OpenStudy (anonymous):
You have :
\[a^3=\frac{125}{8}\]
So :
\[a=\sqrt[3]{\frac{125}{8}}=\frac{5}{2}\]
Now you have :
\[\frac{S_2}{S_1}=a^2=\frac{25}{4}\]
OpenStudy (anonymous):
ohh okay I see. 25 makes more sense.
OpenStudy (anonymous):
so :
\[\frac{S_2}{4}=\frac{25}{4}\]\
so :
\[S_2=25\mathrm{ft}^2\]
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OpenStudy (anonymous):
Okay. I'm going to need to review that so I remember it. Thank you :)
OpenStudy (anonymous):
You are welcome !
OpenStudy (anonymous):
Now for the second one, do you know the formula for a right prism?
OpenStudy (anonymous):
@Noura11
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