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Mathematics 9 Online
OpenStudy (anonymous):

help w/ geometry

OpenStudy (anonymous):

If you can take me through the steps, that'd be awesome.

OpenStudy (anonymous):

For first one, the two solids are similar so we can say that : \[\frac{V_2}{V_1}=a^3\] Where a is number ! Cam you find \[a?\]

OpenStudy (anonymous):

is this for the first or second one?

OpenStudy (anonymous):

It is for the first one !

OpenStudy (anonymous):

don't I do like 4* 8 /125 (2/3) or something. I don't remember...

OpenStudy (anonymous):

or maybe I switch the 8 and 125.

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

You have : \[a^3=\frac{125}{8}\] So : \[a=\sqrt[3]{\frac{125}{8}}=\frac{5}{2}\] Now you have : \[\frac{S_2}{S_1}=a^2=\frac{25}{4}\]

OpenStudy (anonymous):

ohh okay I see. 25 makes more sense.

OpenStudy (anonymous):

so : \[\frac{S_2}{4}=\frac{25}{4}\]\ so : \[S_2=25\mathrm{ft}^2\]

OpenStudy (anonymous):

Okay. I'm going to need to review that so I remember it. Thank you :)

OpenStudy (anonymous):

You are welcome !

OpenStudy (anonymous):

Now for the second one, do you know the formula for a right prism?

OpenStudy (anonymous):

@Noura11

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