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need a little help here. thanks.
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@ganeshie8
\[\large\int\limits_{x_1,y_1}^{x_2,y_2}\nabla f(x,y)\,\mathrm dy\,\mathrm dx=f(x_2,y_2)-f(x_1,y_1)\]
So, find the value on the table that corresponds to (4,1), and from this, take away the value that corresponds to (0,3)
for part b), the start and endpoints of a circular path are the same
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starting point is 4,2 and end point is 4,2
which is just 0
yeah, with the start and endpoints equal the integral of the gradient will be zero
cool. thanks!
what did you get for part a)?
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that means the field is path independent, the work done doesn't depend on the path you take.. and consequently work done along any closed loop will be 0 too
-4
\[\ddot\smile\]
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