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Check my answer pls
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Would this be x= ln(24)/ln(3)
Yes, I would say you were correct
Alright s: because i saw x would be \[x= -\frac{ \ln(24) }{ \ln(3) }\] so i just took the negative sign off
well 3^x
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\[\frac{ 1 }{ 3^{x} }=24\] \[\frac{ 1 }{ 24 }=3^{x}\] \[\ln(\frac{ 1 }{ 24 })=x \ln(3)\]
\[x=\frac{ \ln(\frac{ 1 }{ 24 }) }{ \ln (3) }\]
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