I'm having trouble solving this

2x^2 - 8x = -7

So far I have,

2x^2 - 8x + 7 = 0

Then I plug into the quadratic formula for -

8 +- sqrt{-8^2 - 4(2)(7)}/2(2)

8 +- sqrt{8}/4

Question

I'm having trouble solving this

2x^2 - 8x = -7

So far I have,

2x^2 - 8x + 7 = 0

Then I plug into the quadratic formula for -

8 +- sqrt{-8^2 - 4(2)(7)}/2(2)

8 +- sqrt{8}/4

anonymous · Answer

What's wrong?

anonymous · Answer

I have to simplify 8 +- sqrt{8}/4

anonymous · Answer

hold on and i will post the choices

anonymous · Answer

-2 +- sqrt{2}

-2 +- 2sqrt{2

2 +- sqrt{2}/2 and everything is over 2

2 +- sqrt{2}/2 and only the square root of 2 is over 2

anonymous · Answer

Simplify? Just divide the numerator and denominator by 2. Notice that $\sqrt8$ is $2\sqrt2$

anonymous · Answer

so it is 2 +- sqrt{2}/2 with everything over 2?

anonymous · Answer

|dw:1416337834611:dw|

anonymous · Answer

Exactly. Good work

anonymous · Answer

thank you!

anonymous · Answer

You are welcome