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Mathematics 13 Online
OpenStudy (anonymous):

Two fellow students, Theo and Paula, have added two rational expressions. They ended up with different answers, so they have asked you to check their work. Please explain to them any errors that you find.

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

My teacher said "Great work! Please check Paula's work again to find her error. Remember, she is adding the rational expressions."

OpenStudy (anonymous):

@freckles ganeshie told me to tag you :p

OpenStudy (freckles):

So do you know you can cancel common factors over division not addition?

OpenStudy (freckles):

for example, (assume x doesn't equal 0) \[\frac{x}{x}+\frac{x}{x} \text{ doesn't equal } \frac{x}{\cancel {x}}+\frac{ \cancel{x}}{x}=x+\frac{1}{x} \\ \frac{x}{x}+\frac{x}{x}=1+1=2 \]

OpenStudy (anonymous):

I thought you could cancel common factors in any type of problem like subtraction, addition, division, and multiplication?

OpenStudy (freckles):

nope

OpenStudy (freckles):

another example \[\frac{2}{2}+\frac{2}{2} =1+1=2 \\ \text{ but you cannot say } \\ \frac{2}{2}+\frac{2}{2}=\frac{2}{1}+\frac{1}{2}=2+\frac{1}{2} \]

OpenStudy (freckles):

do you see how 2 and 2+1/2 are not the same ?

OpenStudy (freckles):

so you cannot cancel common factors over addition and/or subtraction

OpenStudy (freckles):

@CrazyTurtle483 do you understand the example?

OpenStudy (freckles):

one is showing what you can do the other part of the example is showing what you cannot do

OpenStudy (anonymous):

Yes I do

OpenStudy (anonymous):

So is that the error in Paula's problem? That she canceled over addition?

OpenStudy (anonymous):

|dw:1416366240682:dw|

OpenStudy (anonymous):

@freckles

OpenStudy (anonymous):

|dw:1416366603842:dw|

OpenStudy (anonymous):

|dw:1416367837275:dw|

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