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Physics 9 Online
OpenStudy (anonymous):

Equilibrium Wheelbarrow

OpenStudy (anonymous):

suppose that you can lift no more than 650N unaided. How much can you lift using a 1.4m long wheelbarrow that weighs 80N with its CG .5m from the center of the wheel. The CG of the load in the wheelbarrow is also .5m from the wheel? Additionally where does the force come from that enables you to lift more than 650N using the wheelbarrow?

OpenStudy (anonymous):

|dw:1416343505876:dw| FBD

OpenStudy (anonymous):

|dw:1416343666936:dw|

OpenStudy (anonymous):

FBD correction

OpenStudy (anonymous):

I took the center of the wheel as the pivot so my toque equations I had setup as \[W2(0.5)=(-80)(0.5)+(650)(1.4)\]

OpenStudy (anonymous):

I got W=1740N, but I am not sure if this is right, and I dont understand where the additional force for lifintg is coming from. Does it mean the normal force of the barrow is helping lift the load?

OpenStudy (anonymous):

@cwrw238

OpenStudy (anonymous):

@Coolsector ,@TheSmartOne

OpenStudy (anonymous):

@TheSmartOne

OpenStudy (surry99):

Physics is fine but you made a math error recalculate W2.

OpenStudy (anonymous):

I'm still getting 1740. Is it that it should be +80?

OpenStudy (surry99):

hang on a sec...be right back.

OpenStudy (surry99):

W = (650*1.4 - 80*.5)/(0.5) = ...see what you get

OpenStudy (anonymous):

1740

OpenStudy (anonymous):

650*1.4=910 80*.5=40 910-40=870 870/.5=870*2=1740

OpenStudy (surry99):

Sorry, my bad...that is correct...I have been looking at to many problems today!

OpenStudy (anonymous):

it's ok thanks for your help. Is the response for the extra lifting force being from the normal force of the barrow acceptable too?

OpenStudy (surry99):

yes

OpenStudy (anonymous):

alright. thank you

OpenStudy (surry99):

welcome ....sorry for the error.

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