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solve sinx^2 + cos2x - cosx = 0 @StudyGurl14
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Sorry, I thought I could help, but know I'm not so sure. @jim_thompson5910
use the substitution \[\cos^(2x) = \cos^2(x) - \sin^2(x)\] and things should become easier
but when you solve equations like that you are supposed to set one side to 0 so you can factor
ohhhhh
i get it, thanks!! but what about the sine and cosine?
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@campbell_st
nevermind, i get it all now thanks!
well you have \[\sin^2(x) + \cos^2(x) - \sin^2(x) - \cos(x) = 0\] so what cancels out...? then you can factor what's left for the solutions
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