Question

Write an equation in slope-intercept form of the line with the given slope and point: slope = 3 and (1, -2). (Points : 1)
y = 3x - 5
y = 3x - 2
y = 3x + 1
y = 3x + 3


Question 6. 6. Write an equation in slope-intercept form for the line shown.
(Points : 1)
y = 2/3 x + 2
y = 3/2 x - 4
y = 3x - 4
y = 2x - 1


Question 7. 7. Write an equation in slope intercept form of the line that passes through (4, 1) and (5, -1). (Points : 1)
y = -4x + 1
y = -1/2 x + 9
y = 4x + 1
y = -2x

Answer 1

Sorry this is so long they are the ones im having trouble with! ho ever helps gets a medal!

Answer 2

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 1}}\quad ,&{\color{blue}{ -2}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies 3
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

is 6.6 supposed to be the slope-intercept of the one above it?

Answer 3

no sorry it was just representing that this is question 6

Answer 4

Write an equation in slope-intercept form for the line shown. <--- where's the "line shown"? then

Answer 5

http://curriculum.kcdistancelearning.com/courses/ALG1x-HS-A06/a/exams/4-HW7/slope_intercept_2.gif

Answer 6

sorry i meant to include that!

Answer 7

6.6 would then be \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 0}}\quad ,&{\color{blue}{ -4}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ -1}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 8

and for 7.7 would be \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 1}})\quad &({\color{red}{ 5}}\quad ,&{\color{blue}{-1}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)

Answer 9

notice, all you do is, get the slope
plug it in the point-slope form along with the coordinates of either given point(s)
and solve for "y"