Question

how do you find the derivative of xe^-2x?

Answer 1

use the product rule and the chain rule

Answer 2

\[(fg)'=f'g+g'f\] with
\[f(x)=x, f'(x)=1,g(x)=e^{-2x}, g'(x)=-2e^{-2x}\]

Answer 3

\[g'\] was found by the chain rule

Answer 4

so the answer is e^-2x + -2e^-2x?

Answer 5

no

Answer 6

\[\huge e^{-2x} -2\color{red}xe^{-2x}\]

Answer 7

great thanks!