Question

Find f(1),f(2),f(3) and f(4), if f(n) is defined recursively by f(0)=1 and for n=0,1,2,3,…
A) f(n+1)=f(n)+2
B) f(n+1)=2^f(n) .

Answer 1

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Answer 2

this is two separate questions right?

Answer 3

\[f(0)=1\\
f(n+)=f(n)+2\]

Answer 4

so
\[f(1)=f(0)+2=0+2=2\] and
\[f(2)=f(1)=2+2=4\] and so on