Question

how do you find the minimum and maximum points of xe^-2x?

Answer 1

take the derivative, set it equal to zero and solve

Answer 2

did you get the derivative yet?

Answer 3

yeoo

Answer 4

what?

Answer 5

yes

Answer 6

by "what" i mean "what did you get?"

Answer 7

-2xe^-2x + e^-2x

Answer 8

ok good, now factor out the common factor of \(e^{-2x}\)

Answer 9

so x=-1/2

Answer 10

yeah i think so

Answer 11

coool thanks

Answer 12

oh no

Answer 13

\[x=\frac{1}{2}\] is what you get when you solve

Answer 14

that will give you the local max

Answer 15

\[(1-2x)e^{-2x}=0\\
x=\frac{1}{2}\]

Answer 16

oh yes i got it thank

Answer 17

yw