Question

Can someone help me with a Chemistry Lab?

Answer 1

So I'm working on this chemistry lab for school it's on Stoichiometry. I have to fill out this table for the lab. I already solved mass, and molar mass. However I need help solving moles of each section, and atoms of each section. Can someone help me solve this section of the lab? I attached the table.

Answer 2

I think it would be helpful if I attached what I already did so far. So Below is updated table with my answers that I have solved so far. I'm willing to take any help anyone can give me.

Answer 3

number of mole = wiegh/Molecular weight

Answer 4

What's the molecular weight?

Answer 5

Molecular weight is the weight of the element such c is 12

Answer 6

you find it in the table of elements

Answer 7

So for C12H22O11 the number of mole would be for
C - 1.202/12
H - 1.202/22
O - 1.202/11
right?

Answer 8

no

Answer 9

So what am I dividing then?

Answer 10

look to the table i just send

Answer 11

So for C12H22O11 the number of mole would be for
C - 1.202/12.01
H - 1.202/1.008
O - 1.202/16.00
right?

Answer 12

for H 1.202/(1*22)=

Answer 13

you are missing the number of atoms

Answer 14

for O = 1.202/(16*11)

Answer 15

and os on

Answer 16

i hope that is clear now

Answer 17

what would be the equation for carbon?

Answer 18

1.201/(12*12)

Answer 19

OK So what about (Au)? I still need the moles and atoms of each elements.

Answer 20

@AJ01 Can you still help me out?

Answer 21

sorry i was off line