Mathematics
9 Online
OpenStudy (anonymous):
line segment help
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OpenStudy (mathstudent55):
A tangent to a circle is perpendicular to the radius that intersects it at the point of tangency.
OpenStudy (mathstudent55):
Then use the Pythagorean theorem.
OpenStudy (anonymous):
I'm not sure. i'm sorry. How would I set that up?
OpenStudy (anonymous):
This is confusing me
OpenStudy (mayankdevnani):
|dw:1416375261837:dw|
use PYTHAGORAS THEOREM
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OpenStudy (anonymous):
so 11.7^2 + 10^2 ?
OpenStudy (mayankdevnani):
\[\large \bf (11.7)^2=(10)^2+r^2\]
OpenStudy (anonymous):
will give me the length of radius?
OpenStudy (mayankdevnani):
no,11.7 is HYPOTENUSE
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OpenStudy (anonymous):
oh
OpenStudy (mayankdevnani):
:)
OpenStudy (anonymous):
Um so wait...
OpenStudy (mayankdevnani):
ok
OpenStudy (anonymous):
yeah I don't know what I'm doing lol 11.7^2 is 136.89 correct?
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OpenStudy (mayankdevnani):
correct
OpenStudy (anonymous):
and 10^2 is 100 so would I just subtract those numbers or...
OpenStudy (mayankdevnani):
yeah
OpenStudy (mayankdevnani):
good going :)
OpenStudy (anonymous):
that's 36.89 but that's none of my options...
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OpenStudy (mayankdevnani):
but you have to take square root of 36.89
because there is r^2
OpenStudy (anonymous):
oh yeah okay I forgot about that. How do I do that on my calculator? I never knew how to
OpenStudy (anonymous):
okay I got 6.07
OpenStudy (mayankdevnani):
\[\large \bf \sqrt{36.89}=6.07\]
OpenStudy (mayankdevnani):
and to nearest tenth,we get 6.0=6
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OpenStudy (mayankdevnani):
so our answer would be 6
OpenStudy (anonymous):
alright thank you :)
OpenStudy (mayankdevnani):
welcome :)