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Mathematics 9 Online
OpenStudy (anonymous):

line segment help

OpenStudy (mathstudent55):

A tangent to a circle is perpendicular to the radius that intersects it at the point of tangency.

OpenStudy (mathstudent55):

Then use the Pythagorean theorem.

OpenStudy (anonymous):

I'm not sure. i'm sorry. How would I set that up?

OpenStudy (anonymous):

This is confusing me

OpenStudy (mayankdevnani):

|dw:1416375261837:dw| use PYTHAGORAS THEOREM

OpenStudy (mayankdevnani):

http://www.mathsisfun.com/pythagoras.html

OpenStudy (anonymous):

so 11.7^2 + 10^2 ?

OpenStudy (mayankdevnani):

\[\large \bf (11.7)^2=(10)^2+r^2\]

OpenStudy (anonymous):

will give me the length of radius?

OpenStudy (mayankdevnani):

no,11.7 is HYPOTENUSE

OpenStudy (anonymous):

oh

OpenStudy (mayankdevnani):

:)

OpenStudy (anonymous):

Um so wait...

OpenStudy (mayankdevnani):

ok

OpenStudy (anonymous):

yeah I don't know what I'm doing lol 11.7^2 is 136.89 correct?

OpenStudy (mayankdevnani):

correct

OpenStudy (anonymous):

and 10^2 is 100 so would I just subtract those numbers or...

OpenStudy (mayankdevnani):

yeah

OpenStudy (mayankdevnani):

good going :)

OpenStudy (anonymous):

that's 36.89 but that's none of my options...

OpenStudy (mayankdevnani):

but you have to take square root of 36.89 because there is r^2

OpenStudy (anonymous):

oh yeah okay I forgot about that. How do I do that on my calculator? I never knew how to

OpenStudy (anonymous):

okay I got 6.07

OpenStudy (mayankdevnani):

\[\large \bf \sqrt{36.89}=6.07\]

OpenStudy (mayankdevnani):

and to nearest tenth,we get 6.0=6

OpenStudy (mayankdevnani):

so our answer would be 6

OpenStudy (anonymous):

alright thank you :)

OpenStudy (mayankdevnani):

welcome :)

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