Question

Calculate K for the oxidation go Iron by H+
(Have worked this problem several times, followed all the appropriate steps and am not getting the same answer as the back of the book)

Answer 1

Answer is: 4.5 * 10^3

Answer 2

I used the equation \[\log_{K} = Ecell \left( \frac{ n }{ 0.0592 V } \right)\]
for n i substituted 6
& my Ecell value was = 0.036

Answer 3

i think what you did is right just continue the problem..
log(k)=3.65
k=10^(3.65)=10^(.65)*10^3= 4.6*10^3