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Calculate K for the oxidation go Iron by H+ (Have worked this problem several times, followed all the appropriate steps and am not getting the same answer as the back of the book)
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Answer is: 4.5 * 10^3
I used the equation \[\log_{K} = Ecell \left( \frac{ n }{ 0.0592 V } \right)\] for n i substituted 6 & my Ecell value was = 0.036
i think what you did is right just continue the problem.. log(k)=3.65 k=10^(3.65)=10^(.65)*10^3= 4.6*10^3
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