Question

I am stuck on this last problem please help

Answer 1

What number must you add to complete the square

X^2+10x=9
10
20
5
25

Answer 2

wrong one sorry

Answer 3

Which of the following correctly completes the square of the equation below
X2+6x=22

(x+6)^2=31
(x+6)^2=25
(x+3)^2=25
(x+3)^2=31

Answer 4

You've got your quadratic formula: \(ax^2 +bx+c=0\)

Answer 5

In completing the square, you take your 'b' value, divide it by 2, and square it.

Answer 6

first put your equation is standard, quadratic form, stated in the previous post.

Answer 7

\[x^2 +10x -9=0\]\[c = \left(\frac{10}{2}\right)^2 = \color{blue}{25}\]\[x^2 +10x +\color{blue}{25} = 0\]

Answer 8

but how come when I squred it I got 9

Answer 9

What are you squaring? Walk me though it.

Answer 10

I did 6/2 I got 3 then did 3^2 got 9

Answer 11

Oh you're referring to your other problem.

Answer 12

Which of the following correctly completes the square of the equation below
X2+6x=22

(x+6)^2=31
(x+6)^2=25 this so its either
(x+3)^2=25this
(x+3)^2=31

Answer 13

Alright, and you are right. It is 9.

Answer 14

but its not in any of the options that's wat im fonfused about

Answer 15

So this is how I'd go about looking at it. One min.

Answer 16

\[x^2 +6x = 22\]\[(x^2+6x) - 22=0\] I put parenthesis around the first two variables as they act like our "ax^2 +bx" and -22 is the potential "c" that we are trying to figure out.

Are you with me so far?

Answer 17

yah

Answer 18

Alright.

Answer 19

\[(x^2+6x) - 22=0\] Now we need to expand what's inside the parenthesis to fit the form "ax^2 +bx +c", to do that, we take (6/2)^2 =9, which you got, good job, \(\checkmark\) \[(x^2 +6x +9)-22=0\] Now this equation is only half right. because we added 9 inside the parenthesis to complete the square, we also need to subtract is when pulling it out of the parenthesis to keep the same format of the original equation. "x^2 +6x = 22"\[(x^2 +6x +9) - 22-9=0\]

Still with me?

Answer 20

yah

Answer 21

Great! An easy way to simplify the quadratic, (stuff inside the parenthesis) is to remember that (b/2) is what the quadratic is simplified into. \[(x^2 +6x +9)-22 -9=0\]\[(x+3)^2 -31=0\] See how we did that?

Answer 22

ohh yes I do

Answer 23

Then we just put the constant on the other side, and you'll find that as one of your answer choices :) \[(x+3)^2 = 31\]

Answer 24

ok thanks

Answer 25

ewwwwwwwwwwwww maths

Answer 26

why did you send this to meh ;~;

Answer 27

math gets me soo stressed lol

Answer 28

SO yeah, are you good? understand how it works?

Answer 29

I actually have one more of these kind of problems and yah im starting to understand it more

Answer 30

maths is of the devil

Answer 31

correction: maths is the devil

Answer 32

Try following the steps I showed you here and figuring it out on your own :) THen tag me and ill check it

Answer 33

to enjoy it is idolatry

Answer 34

xD

Answer 35

ok thx