Question

Simplify the expression.
cos x + sin x tan x

Answer 1

is it sec x ?

Answer 2

Yes, yes it is!

Answer 3

Thank you Batmaan!

Answer 4

\[cosx+sinxtanx = cosx+sinx (\frac{ sinx }{ cosx })\]

Answer 5

\[\large \rm \dfrac{adj}{hyp} + \dfrac{opp}{hyp} \dfrac{opp}{adj}\]

Answer 6

\[cosx+\frac{ \sin^2x }{ cosx } \implies \frac{ \cos^2x+\sin^2x }{ cosx } \implies secx\]

Answer 7

I now understand. Thank you both for the help/ explanation :)

Answer 8

Yeah, just remember the identity cos^2x+sin^2x, so 1/cosx = secx

Answer 9

cos^2x+sin^2x = 1*

Answer 10

Also, welcome back :P

Answer 11

I will! and awesome to see you