Six kilograms of an inferior tea is mixed with 3 kilograms of tea that costs $2 a kilogram more. The total price of the mixture is $24. What is the price of the inferior tea?

Question

jhannybean · Answer

"Six kilograms of an inferior tea is mixed with 3 kilograms of tea that costs $2 a kilogram more" 

Let x = inferior tea, y = more expensive tea 

6x + 3y = 2

"The total price of the mixture is $24." 

x + y = 24

jhannybean · Answer

Now that you have a system of equations, you can use the substitution or elimination method to solve for both variables.

anonymous · Answer

Can you expand it a bit further?

jhannybean · Answer

expand? What are we expanding.

anonymous · Answer

Is it 24$ per kilogram for the new mixture or is it total for all 9 kilograms? if it is total you can just use 6x + 3(x+2) = 24 and solve for x which gives you x = 2.
If it is 24$ per kilogram it will be 6x + 3(x+2) = 9*24 which gives you x = 23.33

shinalcantara · Answer

Six kilograms of an inferior tea is mixed with 3 kilograms of tea that costs $2 a kilogram more. The total price of the mixture is $24
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Let 'x' be the price of inferior tea
6x + 3(x+2) = 24
Distribute 3 to the quantity (x+2)
6x + 3x + 6 = 24
transpose 6 to the right side
6x + 3x = 24 - 6
Combine like terms
9x = 18
Divide the whole equation by 9
x = 2
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Therefore the inferior tea costs $2 per kg