Show that days with the identical calendar date in the years 1999 and 1915 fell on the same day of the week.
whats so special about 1999 :O or 1915
so basically we need to avoid one years each 4 years and count more 7 to get a year with same identical calendar date ... that would be each two 11 years and one 6 years
so, 1999-1915=0 mod 7 xD
bhahaha xD
this is nice to show what day next year would be
I see... if you have time could you help me with solution
solution for what :O
i mean proof
like proper proof ? ok , main i dea is to show that 1999-1915 =0 mod 7
\[Y_1 \equiv Y2 \pmod {7}\] doesnt necessarily mean they will have exact same "day name" on each day of the entire year rigt ?
If thats the case we will be having that pattern every 7 years i guess
nope , count 7+4=11 when we have leap in the start and 7-1 when we dont have
thats for advancing a year ?
?
Join our real-time social learning platform and learn together with your friends!