Suppose a segment of mitochondrial DNA (mtDNA) is compared between two similar modern-day species. It is known that this segment of mtDNA changes at a steady rate of one base pair every 4 million years. Compare the sequences of the two mtDNA segments given below. Species A: GCACTAAGCATCGATTT Species B: GCACCAGGCACTGGTTC Use the basic principle of molecular clocks to calculate how long ago the two species diverged from a common ancestor.
Here's a similar question. @Jhannybean
This is what I got: \(6~differences \cdot \dfrac{4~million~years}{1~mutation} = 24~million~years~ago\)
Oh this is just doing the reverse process.
Is that one of the answer choices?
Yep.
12 million years ago 8 million years ago 48 million years ago 24 million years ago
And the others? They probably don't make sense, anyway.
So backtracking, last question we found the initial set of differences that was 5, but we needed 8. 5/80 = 1/16 , leaving us with 3 more differences. Within an approximation of 80 years, we found about how many years it would take us to fully complete 8 change of bases.
With that we got what would be approx 48 years, right?
Yep.
So yes, I think your approach is correct.
Okay, thanks.
You're saying that it'll take 24 mil. years to make 6 changes, as compared to the 4 years to make 1 change in the sequence.
Yep. \(Number~of~changes \times rate~of~mutation = how~long~ago~the~two~species\) \(~diverged~from~a~common~ancestor.\)
Yeah :)
24 was wrong.. @Jhannybean >.> I have no idea why.
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