The mass of a quantity of NiCl2 is 24.6 g. How many formula units are in the sample? A. 3.2 3 10^23 NiCl2 formula units B. 1.1 3 10^23 NiCl2 formula units C. 1.9 3 10^27 NiCl2 formula units D. 5.3 3 10^-21 NiCl2 formula units
@JFraser Can you help?
can you find the molar mass of \(NiCl_2\)?
129.5994 g/mol correct?
good. i'm going to round up to 130, just to make it faster
ONE mole of \(NiCl_2\) will weigh 130g, that's what the molar mass tells us
but you don't have 130g, you've only got 24.6g
Okay.. So, what do I do next to get this? My mind has gone blank..
one mole of anything is always the same \(number\) of things, right?
Yeah?
so \[1 mole \space NiCl_2 \space = \space 6.02*10^{23} \space units \space NiCl_2 = 130g\]
So, would it be D?
it's not D. you need to set up an equality of fractions
\[\frac{6.02*10^{23} units}{130g} = \frac{?? units}{24.6g}\]
Oh!! Okay, so set up that using the numbers in each option to see which one works best?
no, solve the equality for the missing piece and compare it to the options
So, would it be B?
it is
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