Mathematics
9 Online
OpenStudy (anonymous):
Find the x value for point F such that DF and EF form a 1:3 ratio.
D(-3, -3), E(2, 4)
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OpenStudy (anonymous):
I'm confused
OpenStudy (anonymous):
honestly me too. @KamiBug @StudyGurl14
OpenStudy (anonymous):
They should be able to help
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
yep
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OpenStudy (studygurl14):
Okay hold on a sec.
OpenStudy (anonymous):
ok
OpenStudy (studygurl14):
you have to find a point on the graph that will make the ratio of the lengths of sides DF and EF to be 1:3
OpenStudy (anonymous):
yes i understood that. do you think it is -1.75
OpenStudy (anonymous):
3+2=5 distance
5*1/4=1.25
1.25-3=-1.75
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OpenStudy (anonymous):
taht the only choive that can be made
OpenStudy (anonymous):
am i right?
OpenStudy (anonymous):
look at the grath. it looks like this
OpenStudy (studygurl14):
what is the coordinate @ttb123456789 that's the only way i can check...
OpenStudy (anonymous):
we should find only the x value.
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OpenStudy (anonymous):
@StudyGurl14 are you there
OpenStudy (anonymous):
i'm pressing sumbit. Are you sure that i'm correct?
OpenStudy (studygurl14):
I don't know...i think so.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
@KamiBug
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OpenStudy (kamibug):
Yeah I think that must be pretty close. I'd estimate the x value is near -1.6. So go for it! ^.^
OpenStudy (anonymous):
Geart Thank you guy